A girl and her dog together freight 140 pounds. If the girl weigh 10 pounds smaller quantity than she does,?
Answers: consent to x be the girl's weight
permit y be the dog's weight
x + y =140
if the girl weigh 10 less than she does i.e x-10, this integer would be y +100
x-10=y+100
=> x-y = 90
x + y =140
x - y = 90
add them up,
2x = 230
x= 115
y= 140-115= 25
dog's substance is 25 pounds.
dog 15 girl 125. All you have to do is look at the details of the examine. If -10 from girls weight after girl +100 than dog. 125-10=115 which is +100 than 15. 125 + 15= 140 this is the correct solution. girl is 130
let dog = d and girl = g
immediately from the question
g + d = 140 >>> So g = 140 - d
and
g - 10 = d + 100 >>> Replacing g = 140 - d
140 - d - 10 = d + 100
> 130 - 100 = 2d
> d = 15
So dogs bulk is 15 and girls weight is (140 - 15) = 125
The dog's counterweight is X.
140 = (x) + (x+100-10)
140 = 2x +90
50 = 2x
25 = x
Dog is 25 pounds
Girl is 115 pounds